P^2-p=(p+20)/6

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Solution for P^2-p=(p+20)/6 equation: 



^2-P=(P+20)/6

We move all terms to the left:

^2-P-((P+20)/6)=0

We add all the numbers together, and all the variables

-1P-((P+20)/6)=0

We multiply all the terms by the denominator


-1P*6)-((P+20)=0

Wy multiply elements

-6P^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$P=\frac{-b}{2a}=\frac{0}{-12}=0$

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